So negative 2 is less than orĮqual to x, which is less than or equal to 5. So on and so forth,īetween these integers. In between negative 2 and 5, I can look at this graph to see Negative 2 is less than orĮqual to x, which is less than or equal to 5. What is its domain? So once again, this function It never gets above 8, but itĭoes equal 8 right over here when x is equal to 7. Value or the highest value that f of x obtains in thisįunction definition is 8. Or the lowest possible value of f of x that we get What is its range? So now, we're notįunction is defined. Is less than or equal to 7, the function isĭefined for any x that satisfies this double Here, negative 1 is less than or equal to x Way up to x equals 7, including x equals 7. So it's defined for negativeġ is less than or equal to x. This function is not definedįor x is negative 9, negative 8, all the way down or all the way What is its domain? Well, exact similar argument. Is less than or equal to x, which is less thanĬondition right over here, the function is defined. To determine the median of numbers in the data set, simply find the middle value. So the domain of thisĭefined for any x that is greater than orĮqual to negative 6. To determine the mean, simply divide the total sum of all of the values in the data set by the total number of values as follows: Step 02: Find the Median The median is the middle number or value of a data set. Wherever you are, to find out what the value of It only starts getting definedĪt x equals negative 6. It's not defined for xĮquals negative 9 or x equals negative 8 and 1/2 or Is equal to negative 9? Well, we go up here. We say, well, what does f of x equal when x Is the entire function definition for f of x. Right over here, we could assume that this What is its domain? So the way it's graphed One more point (0,6) would give 6>3 which is a true statement, and shading should include this point. If point is (1,5) you can do the same thing, 5 > 5, but this would be right on the line, so the line would have to be dashed because this statement is not true either. If you try points such as (0,0) and substitute in for x and y, you get 0 > 3 which is a false statement, and if you did it right, shading would not go through this point. So lets say you have an equation y > 2x + 3 and you have graphed it and shaded. The has to do with the shading of the graph, if it is >, shading is above the line, and ). Without the "equal" part of the inequality, the line or curve does not count, so we draw it as a dashed line rather than a solid line The "equal" part of the inequalities matches the line or curve of the function, so it would be solid just as if the inequality were not there.
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